# How do I count items in a list based on a condition in Python

There are many ways to count the occurrences of items in a list based on a condition. Here you will see two of them: one example with map and one example by using list comprehension.

Start by creating a list of names. Note that chuck appears twice in the list.

``````>>> names = ["vera", "chuck", "dave", "chuck"]
>>> names
['vera', 'chuck', 'dave', 'chuck']
``````

## Count occurrences by using Map

By using map you can provide a lambda with the condition like this:

``````>>> map(lambda x: x == "chuck", names)
<map object at 0x102f4dc18>
``````

This results in a map object that we can inspect by converting it to a list:

``````>>> list(map(lambda x: x == "chuck", names))
[False, True, False, True]
``````

You see that the map has converted the values in the list `names` to boolean values. If you replace list with sum, Python will calculate the total of `True` values:

``````>>> sum(map(lambda x: x == "chuck", names))
2
``````

## Count occurrences by using List comprehension

List comprehension is another way to map lists to create new lists. You can start by using a list comprehension that does not filter the list at all and thus returns a copy of the original list:

``````>>> [n for n in names]
['vera', 'chuck', 'dave', 'chuck']
``````

To filter that list, you can use `if`:

``````>>> [n for n in names if n == "chuck"]
['chuck', 'chuck']
``````

Now use the `len` function to count the occurrences:

``````>>> len([n for n in names if n == "chuck"])
2
``````
Written by Loek van den Ouweland on February 13, 2019. Questions regarding this artice? You can send them to the address below.